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Basis of a Vector Space

Basis

Vector space is said to be finite-dimensional if \exists a finite number of vectors such that the vector space (L,+,.)=(E,+,.)(L,+,.)=(E,+,.) where the span LL is L(v1..)L(v_1..).

A basis B={v1...}B=\{v_1...\} of (E,+,.)(E,+,.) is a set of vectors E\in E that verify the following properties:

Null Vector and Linear Dependence

If one of the vectors is equal to the null vector, then these vectors are linear dependent

Steinitz Lemma

(E,+,.)(E,+,.) = Finite-dimensional vector space L(v1..)=EL(v_1..)=E = E its span Let w1...w_1... be ss linearly independent vectors E\in E Follows that sns\le n, the number of a set of linearly independent vectors cannot be higher than the number of vectors spanning the vector space.

Corollary of the Steinitz Lemma

^continuation B={w1...}B=\{w_1...\} be its basis, it follows that sns\le n. The vectors composing the basis are linearly independent. For the Steinitzs Lemma, it follows immediately that sns\le n

Dimension of a Basis

Order of a Basis

Number of vectors composing a basis is said order of a basis All the bases of a vector spaces have the same order

Dimension of a Vector Space

The order of a basis is said dimension is indicated with dim (E,+,.)(E,+,.) or dim(EE). The dimension dim (E,+,.)=n(E,+,.)=n of a vector space is:

  • the maximum number of linearly independent vectors of E
  • the minimum number of vectors spanning E

Linear independence and dimension

The vectors span the vectors if and only if they are linearly independent

Grassmann Formula

Reduction and Extension of a basis

Basis Reduction Theorem - If some vectors are removed a basis of (E,+,.)(E,+,.) is obtained Basis Extension Theorem - Let w1..w_1.. be ss linearly independent vectors of the vector space. If w1..w_1.. are not already a basis, they can be extended to a basis (by adding other linearly independent vectors)

Unique Representation

If the nn vectors are linearly dependent while n1n-1 is linearly independent, there is a unique way to express one vectors as linear combination of others (How you would represent other lines with one another, identify them with lambdas)

Grassmanns Formula

Let (U,+,.)(U,+,.) and (V,+,.)(V,+,.) be vector subspace of (E,+,.)(E,+,.). Then, dim(U+V)+dim(UV)=dim(U)+dim(V)dim(U+V)+dim(U\cap V) = dim(U) + dim(V)